2[2X-2+2X]=3(2X-4)+32

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Solution for 2[2X-2+2X]=3(2X-4)+32 equation:


Simplifying
2[2X + -2 + 2X] = 3(2X + -4) + 32

Reorder the terms:
2[-2 + 2X + 2X] = 3(2X + -4) + 32

Combine like terms: 2X + 2X = 4X
2[-2 + 4X] = 3(2X + -4) + 32
[-2 * 2 + 4X * 2] = 3(2X + -4) + 32
[-4 + 8X] = 3(2X + -4) + 32

Reorder the terms:
-4 + 8X = 3(-4 + 2X) + 32
-4 + 8X = (-4 * 3 + 2X * 3) + 32
-4 + 8X = (-12 + 6X) + 32

Reorder the terms:
-4 + 8X = -12 + 32 + 6X

Combine like terms: -12 + 32 = 20
-4 + 8X = 20 + 6X

Solving
-4 + 8X = 20 + 6X

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-6X' to each side of the equation.
-4 + 8X + -6X = 20 + 6X + -6X

Combine like terms: 8X + -6X = 2X
-4 + 2X = 20 + 6X + -6X

Combine like terms: 6X + -6X = 0
-4 + 2X = 20 + 0
-4 + 2X = 20

Add '4' to each side of the equation.
-4 + 4 + 2X = 20 + 4

Combine like terms: -4 + 4 = 0
0 + 2X = 20 + 4
2X = 20 + 4

Combine like terms: 20 + 4 = 24
2X = 24

Divide each side by '2'.
X = 12

Simplifying
X = 12

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